1.

Two forces each of magnitude 2N act vertically upwards and downwards respectively at the two ends of a uniform rod of length 1m which is pivoted at its centre. Draw a diagram of the arrangement and determine the resultant moment of forces about the mid point of the rod.

Answer»

Solution :The arrangement is shown in fig.1.21 GIVEN below . AB is the ROD which is pivoted at its centre O.

Given `AB=1m therefore OA=OB=0.5m`
Moment of force F (=2N) at A about the POINT O
`=F TIMES OA =2 times 0.5 =1.0 Nm` (clockwise)
Moment of force F (=2N) at B about the point O
`=F times OB=2 times 0.5=1.0 Nm` (clockwise)
`therefore` TOTAL moment of forces about the mid point O
`=1.0+1.0=2.0 N m` (clockwise)


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