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Two hydrogen gas balloons having the same pressure and whose volumes are in the ratio of 1:2, resoectively, are relased simultaneously into air on the surface of the Earth. Find the ratio of time taken to reach a height of 100 m from the ground. (Neglect the air friction) |
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Answer» Solution :`1:1` `F_("Net")=U-W` `V_(b)d_(b)a_("Nrt")=V_(b)*d_("air")*g-V_(b)*d_(b)*g` `a_("Net")=(g(d_("air")-d_(b)))/(d_(b))` `a_("Net")` is independent of volume of the BODY. Here the two BALLOONS have same pressure, so their DENSITIES will also be equal. Therefore, they take same time to reach the given height. |
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