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Two identical blocks A and b of different materials float on water such that 90% of A and 15% of B remain submerged inside water. Compare: (i) density of A and B. |
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Answer» SOLUTION :Given for block `A:V/V=90%=0.9` for block B: `v/V=15%=0.15` (i) If `rho_(A),rho_(B)` and `rho_(w)` are the densities of A,B and water then For block `A=v/V=(rho_(A))/(rho_(w))=0.9`…I For block `B=v/V=(rho_(E))/(rho_(w))=0.15` ………II DIVIDING eqn (i) by eqn (ii) we get `(rho_(A))/(rho_(B))=0.9/0.15=6:1` (ii) It V is the volume of each block `("UPTHRUST on A")/("Upthrust on B")=(Vrho_(A)g)/(Vrho_(B)g)=(rho_(A))/(rho_(B))=6:1` |
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