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Two identical resistors are first connected in series and then in parallel. Find the ratio of equivalent resistances in two cases.

Answer»

SOLUTION :Let two resistors of value R each are first joined in series, when equivalent resistance
`R_s=R+R=2R`
On JOINING these very resistors in parallel let equivalent resistance be `R_p`, where
`1/R_p=1/R+1/R=2/R implies R_p=2/R`
`THEREFORE R_s/R_p=(2R)/((R/2))=4/1`


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