1.

Two identical resistors each of resistance 10 Omega are connected (i) in series and then (ii) in parallel, in line to a battery of 6 volts. Calculate the ratio of power consumed in the combination of resistors in the two cases.

Answer»

SOLUTION :Here `R_1=R_2=10 OMEGA` and V=6 volt
(i) In series NET resistance `R_s=R_1+R_2=10+10=20 Omega`
and Power `P_s=V^2/R_s=(6)^2/20=1.8 W`
(II) In parallel net resistance `1/R_p=1/R_1+1/R_2=1/10+1/10=1/5 implies R_p=5 Omega`
and Power `P_p=V^2/R_p=(6)^2/5=7.2 W`
`implies P_s/P_p=1.8/7.2=1/4`


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