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Two liquids X and Y from an ideal solution at`300K`, Vapour pressure of the Solution containing `1`mol of X and `3`mol of Y is `550`mmHg . At the same temperature, if `1` mol of Y is further added to this solution ,vapour pressur of the solutions increases by `100`mmHg Vapour pressure (in mmHg) of X and Y in their pure states will be,respectivelyA. 200 and 300B. 300 and 400C. 400 and 600D. 500 and 600 |
Answer» Correct Answer - C `550=P_(x)^(0).(1)/(4)+P_(y)^(0).(3)/(4)` ………(i) after adding 1 mole of y further `560=P_(x)^(0).(1)/(5)+P_(y)^(0).(4)/(5)` …………(ii) solving (i) & (ii) `P_(x)^(0)=400 MM` `P_(y)^(0)=600 MM` |
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