1.

Two mixtures M1 and M2 contain mixture of two types of pulses P1 and P2. M1 and M2 contain P1 and P2 in the ratio of 4 : 5 and 8 : 3 respectively. M1 and M2 are mixed to form a third mixture. Now the ratio of P1 : P2 becomes 8 : 5 in the resultant mixture. Find the amount of pulses P2 in the M2, if the resultant quantity is 364 kg of pulses.1). 62 kg2). 64 kg3). 60 kg4). 68 kg

Answer»

P2 in M1 = 5/9, in M2 = 3/11 and in resultant mixture = 5/13

By ALLIGATION rule : -

5/9 3/11

5/13

(5/13 – 3/11) = 16/143 (5/9 – 3/11) = 20/117

⇒ 16/143 : 20/117 = 36 : 55

∴ Amount of M2 in 364 kg = 55/91 × 364 = 220 kg

Now amount of pulses P2 in M2 = (3/11) × 220 = 60 kg


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