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Two pendulum of different angle are in pgase at mean position at a cartain The minimum and after which they will be again in phase is `5T//4` where in the period of shaorter pendulum find the ratio length of the two pendulumA. `1:16`B. `1:4`C. `1:2`D. `1:25` |
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Answer» Correct Answer - D Let `T_(1) = T and T_(2) = KT,(2pi)/(T) t - (2pi)/(KT) t = 2pi` `t((K - 1)/(KT)) = 1, ((K - 1)/(KT)) = 1 which given K = 5` If length of first pendulum `= t, T_(1) = 2pi sqrt(1//g)` `T_(2) = 5 xx sqrt(1//g) = 2pi sqrt(25//g)` So ratio of length `= 1: 25` |
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