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Two pipes, A and B can fill a tank in 16 and 20 hours respectively. If both are opened together and at the end of 4 hours pipe A is closed, How long will the pipe B take to fill the remaining part of the tank?1). 11 hours2). 13 hours3). 16 hours4). 9 hours |
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Answer» Given, A and B can FILL a tank in 16 and 20 HOURS respectively In 1 hr, A can fill 1/16 of the tank. B can fill 1/20 of the tank. Together, PART of the tank filled by them in 1 hr, = 1/16 + 1/20 = 9/80 Given, they are opened for 4 hours together and then A is closed. Thus part of tank filled in 4 hr $(= 4 \TIMES \frac{9}{{80}} = \frac{9}{{20}})$ Part of tank remaining = 1 – 9/20 = 11/20 ∴ Pipe B will fill the rest of the tank in time $(= \frac{{\frac{{11}}{{20}}}}{{\frac{1}{{20}}}} = 11\;hours)$ |
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