Two radioactive materials have decay constant `5lambda&lambda`. If initially they have same no. of nuclei. Find time when ratio of nuclei become `((1)/(e))^(2)` :

Two radioactive materials have decay constant `5lambda&lambda`. If ini

1.	Two radioactive materials have decay constant `5lambda&lambda`. If initially they have same no. of nuclei. Find time when ratio of nuclei become `((1)/(e))^(2)` :
Answer» Correct Answer - D `N = N_(0)e^(-lambdat)` `N_(A) = N_(0)e^(-5lambdat)` `N_(B) = N_(0)e^(-lambdat)` `(N_(A))/(N_(B)) = e^(-4lambdat) rArr ((1)/(e))^(2) = ((1)/(e))^(4lambdat)` `4lambdat = 2 rArr t = (1)/(2)lambda`

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Two radioactive materials have decay constant `5lambda&lambda`. If initially they have same no. of nuclei. Find time when ratio of nuclei become `((1)/(e))^(2)` :

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