InterviewSolution
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InterviewSolution
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Two resistors with resistance of 10 Omega and 15 Omega are connected to a battery of 12V so as to obtain and measure (i) minimum electric current, (ii) maximum electric current . (a) State the mode of connecting the resistors in each case with the help of a circuit diagram. (b) Calculate the strength of total electric current in the circuit in each case. |
Answer» SOLUTION :(a) To obtain MAXIMUM electric current the resistors should be connected in series as shown in diagram (a) TO obtain maximum electric current the resistors should be connected in parallel as shown in diagram (B)  (b) In series ARRANGEMENT `R_s=R_1+R_2=10+15=25 Omega` `therefore` CIrcuit current `I_(MIN)=V/R_s=12/25=0.48 A` In parallel arrangement `1/R_p=1/R_1+1/R_2=1/10+1/15=(3+2)/30=5/30=1/6 implies R_p=6 Omega` `therefore` Circuit current `I_(max)=V/R_p=(12 V)/(6 Omega)=2A` |
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