Two simple harmonic are represented by the equation `y_(1)=0.1 sin (100pi+(pi)/3) and y_(2)=0.1 cos pit`. The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is.A. `(-pi)/(3)`B. `(pi)/(6)`C. `(-pi)/(6)`D. `(pi)/(3)`

Two simple harmonic are represented by the equation `y_(1)=0.1 sin (10

1.	Two simple harmonic are represented by the equation `y_(1)=0.1 sin (100pi+(pi)/3) and y_(2)=0.1 cos pit`. The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is.A. `(-pi)/(3)`B. `(pi)/(6)`C. `(-pi)/(6)`D. `(pi)/(3)`
Answer» Correct Answer - C `v_(1) = (dy_(1))/(dt) = - 0.1 xx 100pi cos(100 pi t + (pi)/(3))` `v_(2) = (dy_(2))/(dt) = - 0.1 pi sin pi t = 0.1 pi cos(pi t + (pi)/(2))` phase difference of velocity of first particle with respect to the velocity of `2^(nd)` particle at `t = 0` is `Delta phi = phi_(1) - phi_(2)= (pi)/(3) - (pi)/(2)= -(pi)/(6)`

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Two simple harmonic are represented by the equation `y_(1)=0.1 sin (100pi+(pi)/3) and y_(2)=0.1 cos pit`. The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is.A. `(-pi)/(3)`B. `(pi)/(6)`C. `(-pi)/(6)`D. `(pi)/(3)`

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