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`U^(235) + n^(1)rarr` fission product + neutron + 3.2`xx 10^(-11)j`. The energy released , when 1g of `u^(235)` finally undergoes fission , isA. `12.75xx10^(8)kj`B. `18.60xx10^(9)kj`C. `8.21xx10^(7)kj`D. `6.55xx10^(6)kj` |
Answer» Correct Answer - C 235 g of u-235 contains `6.023xx10^(23)` atoms 1g u-235=`(6.023xx10^(23))/(235)atoms` `therefore` Energy relaeased =`(3.2xx10^(-11)xx6.023xx10^(23))/(235)j` `=8.21xx10^(10)j` `8.21xx10^(7) kj` |
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