InterviewSolution
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InterviewSolution
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`U^(238)` is found to be in secular equilibrium with `Ra^(226)` in its ore. If chemical analysis shown `1` atoms of `Ra^(226)` per `2.8xx10^(6)` atoms of `U^(238)`, find the half-like of `U^(228)`. Given the half life `Ra^(226)` is `1620` years. |
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Answer» For secular equilibrium `lambda_(U)N_(U) = lambda_(Ra)N_(Ra)` `(ln2)/((T_(1//2))_(U))N_(U) = (ln2)/((T_(1//2))_(Ra))N_(Ra)` `(2.8xx10^(6))/((T_(1//2))_(U)) = (1)/(1620)` `(T_(1//2))_(U) = 4.5 xx 10^(9)` year |
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