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Use the mirror equation to show that an object placed between `f and 2f` of a concave mirror forms an image beyond `2f`. |
Answer» Let `u = -(3 f)/(2)`, when object lies between f and 2f. `(1)/(v) + (1)/(u) = (1)/(f)` `(1)/(v) = (1)/(f) - (1)/(u) = (-1)/(f) + (2)/(3f) = (-3 + 2)/(3f) = -(1)/(3f)` For concave mirror, `f` is neg. `v = -3f` i.e., distacne of image from the concave mirror is `3f`, i.e., image formed is beyond `2f`. |
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