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Usha swims in a 90 m long pool. She covers 180 m in one minute by swimming from one end to the other and back along the same straight path. Find the average speed and average velocity of Usha. |
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Answer» Solution :TOTAL DISTANCE covered by Usha in 1 min is 180 m. Displacement of Usha in `1 min =0 m ` AVERAGE speed `= (" Total distance covered")/("Total time taken") = (180m )/(1 mn)` `= (180 m)/(1 min ) x (1 min)/(60 s)` `= 3 ms ^(-1)` Average velocity `= ("Displacement")/("Total time taken") = (0M)/(60S ) = 0 m s ^(-1)` The average speed of Usha is `3 ms ^(-1) and ` her average velocity is `0 ms ^(-1).` |
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