1.

Usha swims in a 90 m long pool. She covers 180 m in one minute by swimming from one end to the other and back along the same straight path. Find the average speed and average velocity of Usha.

Answer»

Solution :TOTAL DISTANCE covered by Usha in 1 min is 180 m.
Displacement of Usha in `1 min =0 m `
AVERAGE speed `= (" Total distance covered")/("Total time taken") = (180m )/(1 mn)`
`= (180 m)/(1 min ) x (1 min)/(60 s)`
`= 3 ms ^(-1)`
Average velocity `= ("Displacement")/("Total time taken") = (0M)/(60S ) = 0 m s ^(-1)`
The average speed of Usha is `3 ms ^(-1) and ` her average velocity is `0 ms ^(-1).`


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