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Vapour pressure of pure water is 40 mm. if a non-volatile solute is added to it, vapour pressure falls by 4 mm. Hence, molarity of solution isA. 6.17mB. 3.09mC. 1.54mD. 0.77m |
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Answer» Correct Answer - A `(Deltap)/(p^(@)) = x_(B)` `x_(B) = (4)/(40) = 0.1` Thus, solution contains 0.1 mol of solute in 0.9 mol of water Mass of water `= 0.9 xx 18 = 16.2 g` Molarity of solution `= (0.1)/(16.2) xx 1000` `=(100)/(16.2) = 6.17m` |
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