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Volume of `0.1M K_(2)Cr_(2)O_(7)` required to oxidise `35 mL` of `0.5M FeSO_(4)` solution isA. `29.2 mL`B. `17.5mL`C. `175 mL`D. `145 mL` |
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Answer» Correct Answer - A `Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-)rarr 2Cr^(3+)+7H_(2)O` `Fe^(2+)rarr Fe^(3+)+e^(-)xx6` `Cr_(2)O_(7)^(2-)+6Fe^(2+)+14H^(+)rarr 2Cr^(3+)+7H_(2)O+6Fe^(3+)` `(M_(1)V_(1))/(n_(1))=(M_(2)V_(2))/(n_(2))` `(Cr_(2)O_(7)^(2-)) ( Fe^(2+))` `(0.1xxV_(1))/(1)=(0.5xx35)/(6)` `V_(1)=(5xx35)/(6)=29.17 mL` |
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