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Wavelength of high enrgy trabsition fo H-atoms is ` 91 . 2 nm`. Calculate the corresponding wavelength of `He^(+)`. |
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Answer» For H- atom : ` 1/( lambda_H) = R_H [ 1/n_1^2 - 1/n_2^2]` ..(1) From `He^+ ion ,` ` 1/( lambda_(He^+)) = R_H xx Z^2 [ 1/n_(2)] ` ` = 91. 2 xx 1/2^2 = 22 . 8 nm`. |
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