InterviewSolution
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InterviewSolution
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Wavelength of light used in an optical instrument are `lambda_(1) = 4000 Å` and `lambda_(2) = 5000Å` then ratio of their respective resolving powers (corresponding to `lambda_(1)` and `lambda_(2)`) isA. `16 : 25`B. `9 : 1`C. `4 : 5`D. `5 : 4` |
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Answer» Correct Answer - D `R.P = (a)/(1.22lambda)` `R.P. prop (1)/(lambda)` `((R.P.)_(1))/((R.P.)_(2)) = (lambda_(2))/(lambda_(1)) = (5000)/(4000) = (5)/(4)` |
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