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Wavelength of the Balmer H, line (first line) is `6565 Å`. Calculate the wavelength of `H_(beta)` (second line). |
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Answer» Correct Answer - `4863 A^(@)` `n_(2)=3" "n_(1)=2` [first line] `n_(2)=4" "n_(1)=2` [second line] `(1)/(lambda)=R_(H)[(1)/(4)-(1)/(9)]` `(1)/(6565)Å=R_(H)[(1)/(4)-(1)/(9)]....(i)` `(1)/(lambda)=R_(H)[(1)/(4)-(1)/(16)]...(ii)" "((i))/((ii))` `(lambda)/(6565)=((5)/(36))/((3)/(16))=(5xx16)/(36xx3)" "lambda=4863Å` |
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