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We have 100 mL of 0.1 MKCI solution . To make it 0.2 MA. evaporate `50mL` waterB. evaporate `50mL` solutionC. add `0.1` mol `KCl`D. add `0.01` mol `KCl` |
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Answer» Correct Answer - A::B::D Initial moles of `KCl=(100)/(1000)xx0.1=0.01` Let `x` moles of `KCl` are added, so `0.2=(0.001+x)/(100//1000)` or `x=0.01` |
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