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What amount of `CaCl_2` (i=2.47) is dissolved in 2 litres of water so that its osmotic pressure is 0.5 atm at `27^@` C ?A. 3.42 gB. 9.24 gC. 2.834 gD. 1.820 g |
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Answer» Correct Answer - D `pi=iCRT = I n/V RT` `n=(pixxV)/(ixxRxxT) =(0.5xx2)/(2.47xx0.0821xx300)`=0.0164 mol Amount of `CaCl_2=n xx M =0.0164 xx 111` = 1.820 g |
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