1.

What do you conclude about the speed of light in diamond if the refractive index of diamond is 2.41? way from the mirror. Does the image become smaller or larger? What do you observe?

Answer»

SOLUTION :`MU = 2.41 , Ca = 3 xx 10^(8) ms` [ VELOCITY of light ]
`mu = ( " Speed of light in AIR")/("Speed of light in diamond" ) = (C_a)/(C_d)`
`C_d = (C_a)/( mu ) = (3 xx 10^(8))/(2.41) = 1.245 xx 10^(8)` m/s
`therefore` Speed of light decreases when the light ray travels air to diamond.


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