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InterviewSolution
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What is (a) the highest (b) the lowest total resistance that can be secured by combinations of four coils of resistances 4 Omega,8 Omega,12 Omega and 24 Omega? |
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Answer» Solution :a) To obtain HIGHEST resistance, all the FOUR RESISTANCES must be CONNECTED in series arrangement. In that case RESULTANT resistance `R_s` is given by `R_s=R_1+R_2+R_3+R_4=4+8+12+24=48 Omega` (b) To obtain lowest resistance, all the four resistances must be connected in parallel arrangement, in that case the resultant resistance `R_p` is given by : `1/R_p=1/R_1+1/R_2+1/R_3+1/R_4=1/4+1/8+1/12+1/24=(6+3+2+1)/24=12/24` `R_p=24/12 Omega =2 Omega` |
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