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What is likely to be principal quantum number for a circular orbit of diameter `20nm` of the hydrogen atom if we assume Bohr orbit be the same as that represented by the principal quantum number?A. `10`B. `14`C. `12`D. `16` |
Answer» Correct Answer - B `d=20nm` `r=(20)/(2)=10nm=100Å` `therefore r=0.529xx(n^(2))/(Z)A^(@)` For `H` atom `Z=1` `100=0.529xxn^(2) " "n=14` |
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