1.

What is the area (in cm2) of the rhombus having side as 10 cm and one of the diagonals as 12 cm?1). 922). 963). 944). 98

Answer»

We know that,

All sides of rhombus are EQUAL in length.

Let us find the area of triangle formed by 2 sides of rhombus and 1 diagonal.

By Heron’s formula,

Semi-perimeter, S = (10 + 10 + 12)/2 = 32/2 = 16

Area of triangle $( = \sqrt {s \TIMES \left( {s - a} \right) \times \left( {s - b} \right) \times \left( {s - C} \right)} )$

⇒ Area of triangle $( = \sqrt {16 \times \left( {16 - 10} \right) \times \left( {16 - 10} \right) \times \left( {16 - 12} \right)} )$

⇒ Area of triangle $( = \sqrt {16 \times 6 \times 6 \times 4}= 48)$

∴ Area of rhombus = 48 × 2 = 96 cm2



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