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What is the area (in cm2) of the rhombus having side as 10 cm and one of the diagonals as 12 cm?1). 922). 963). 944). 98 |
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Answer» We know that, All sides of rhombus are EQUAL in length. Let us find the area of triangle formed by 2 sides of rhombus and 1 diagonal. By Heron’s formula, Semi-perimeter, S = (10 + 10 + 12)/2 = 32/2 = 16 Area of triangle $( = \sqrt {s \TIMES \left( {s - a} \right) \times \left( {s - b} \right) \times \left( {s - C} \right)} )$ ⇒ Area of triangle $( = \sqrt {16 \times \left( {16 - 10} \right) \times \left( {16 - 10} \right) \times \left( {16 - 12} \right)} )$ ⇒ Area of triangle $( = \sqrt {16 \times 6 \times 6 \times 4}= 48)$ ∴ Area of rhombus = 48 × 2 = 96 cm2 |
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