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What is the final velocity of an electron accelerating through a potential of `1600 V` if its initial velocity is zero . |
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Answer» Correct Answer - A::B::C `(1)/(2) mv^(2) = eV` `v = sqrt((2eV)/(m)) = [(2 xx 1.6 xx 10^(34) xx 1600)/(9.1 xx 10^(-31))] ` `= 2.37 xx 10^(7) m s^(-1)` |
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