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What is the formula for Lagrange’s theorem?(a) f’(c) = \(\frac {f(a)+f(b)}{b-a}\)(b) f’(c) = \(\frac {f(b)-f(a)}{b-a}\)(c) f’(c) = \(\frac {f(a)+f(b)}{b+a}\)(d) f’(c) = \(\frac {f(a)-f(b)}{b+a}\)I have been asked this question during an interview for a job.Enquiry is from Mean Value Theorem in portion Continuity and Differentiability of Mathematics – Class 12

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Right answer is (b) f’(C) = \(\FRAC {f(b)-f(a)}{b-a}\)

Explanation: ACCORDING to Lagrange’s mean value theorem, if f : [a,b] → R is a function such that f is differentiable on (a,b) then the FORMULA for Lagrange’s theorem is f’(c) = \(\frac {f(b)-f(a)}{b-a}\).



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