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What is the formula to find the rise in the water level when ‘x’ spherical balls are dropped into a cylindrical beaker?(a) \(\frac {Volume \, of \, ‘x’ \, spherical \, balls}{Base \, area \, of \, cylinder}\)(b) \(\frac {Volume \, of \, ‘x’ \, spherical \, balls}{2(Base \, area \, of \, cylinder)}\)(c) The volume of the cylinder + volume of the beaker(d) The volume of the cylinder – 2(volume of the beaker)This question was addressed to me at a job interview.Origin of the question is Conversion of Solid from One Shape to Another topic in portion Surface Area and Volumes of Mathematics – Class 10

Answer»

Correct option is (a) \(\frac {VOLUME \, of \, ‘x’ \, spherical \, BALLS}{Base \, AREA \, of \, cylinder}\)

Explanation: To find the rise in the water LEVEL we require the volume of ‘x’ spherical balls and the base area of the cylinder

Rise in the water level = \(\frac {Volume \, of \, ‘x’ \, spherical \, balls}{Base \, area \, of \, cylinder}\)



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