1.

What is the fraction of the solute in a `1.00` m aqueous solution ?A. 1.77B. 0.177C. 0.0177D. 0.0344

Answer» Correct Answer - 3
`1.00` molal aqueous solution means `1 mol` of the solute is present in enery `1 kg (1000 g)` of solvent Considering `1 kg` of solvent, we have
`n_(solute)=1`
`n_(solvent)=(m_(H_(2)O))/(mm_(H_(2)O))=(1000g)/(18 g//mol)`
`=55.6 mol`
Thus, `chi_(solute)=n_(solute)/(n_(solute)+n_(solvent))`
`=1/(1+55.6)`
`=0.0177`


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