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What is the fraction of the solute in a `1.00` m aqueous solution ?A. 1.77B. 0.177C. 0.0177D. 0.0344 |
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Answer» Correct Answer - 3 `1.00` molal aqueous solution means `1 mol` of the solute is present in enery `1 kg (1000 g)` of solvent Considering `1 kg` of solvent, we have `n_(solute)=1` `n_(solvent)=(m_(H_(2)O))/(mm_(H_(2)O))=(1000g)/(18 g//mol)` `=55.6 mol` Thus, `chi_(solute)=n_(solute)/(n_(solute)+n_(solvent))` `=1/(1+55.6)` `=0.0177` |
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