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What is the frequency of photon, whose momentum is `1.1xx10^(-23) kg ms^(-2)`A. `5xx10^16` HzB. `5xx10^17` HzC. `0.5xx10^18` HzD. `5xx10^18` Hz |
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Answer» Correct Answer - D `because E=mc^2, E=hv` `therefore mc^2 =hv` `v=(mc^2)/(h)=(1.1xx10^(-23)xx3xx10^8)/(6.6xx10^(-34))=5xx10^18` Hz |
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