1.

What is the frequency of photon, whose momentum is `1.1xx10^(-23) kg ms^(-2)`A. `5xx10^16` HzB. `5xx10^17` HzC. `0.5xx10^18` HzD. `5xx10^18` Hz

Answer» Correct Answer - D
`because E=mc^2, E=hv`
`therefore mc^2 =hv`
`v=(mc^2)/(h)=(1.1xx10^(-23)xx3xx10^8)/(6.6xx10^(-34))=5xx10^18` Hz


Discussion

No Comment Found

Related InterviewSolutions