1.

What is the highest

Answer»

Solution :`1/R=1/(4Omega)+1/(8OMEGA)+1/(12OMEGA)+1/(24Omega)`
`=(6+3+2+1)/(24)Omega`
`=(12)/(24)Omega=1/2Omega`
When all the resistors are connected in PARALLEL
Thus, R=`2Omega`


Discussion

No Comment Found