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What is the lowest resistance that can be obtained by combining four coils of resistors of 4 Omega,8 Omega ,12 Omega and 24 Omega? |
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Answer» Solution :To obtain lowest RESISTANCE given COILS MUST be CONNECTED in parallel. Then the equivalent resistance will be `1/R=1/R_1+1/R_2+1/R_3+1/R_4=1/4+1/8+1/12+1/24=(6+3+2+1)/24=12/24=1/2 IMPLIES R=2 Omega` |
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