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What is the magnitude of the gravitational force between the earth and a 1 kg object emits surface? (Mass of the earth is 6xx10^(24)kg and radius of the earth is 6.4 xx 10^(6) m).

Answer»

Solution :GIVEN that
MASS of the body, m=1kg
Mass of the Earth, `M=6xx10^(24)kg`.
Radius of the earth, `R=6.4xx10^(6)`
Now and of the gravitational FORCE between the earth and the body can be the
`F=G(Mxm)/(r^(2))=(6.67xx10xx6xx10xx1)/((6.4xx10^(6))^(2))`
`=(6.67xx6xx10)/(6.4xx64.4)=9.8N`.


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