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What is the magnitude of the gravitational force between the earth and a 1 kg object emits surface? (Mass of the earth is 6xx10^(24)kg and radius of the earth is 6.4 xx 10^(6) m). |
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Answer» Solution :GIVEN that MASS of the body, m=1kg Mass of the Earth, `M=6xx10^(24)kg`. Radius of the earth, `R=6.4xx10^(6)` Now and of the gravitational FORCE between the earth and the body can be the `F=G(Mxm)/(r^(2))=(6.67xx10xx6xx10xx1)/((6.4xx10^(6))^(2))` `=(6.67xx6xx10)/(6.4xx64.4)=9.8N`. |
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