1.

What is the minimum velocity required for an object of mass “m” to escape the gravitational pull of a planet of mass “M” and radius “R” from its surface?(a) [(G*M)/R]^1/2(b) [(2*G*M)/R] ^2(c) [(G*M*m)/R]^1/2(d) [(2*G*M)/R]^1/2The question was posed to me in examination.The origin of the question is Gravitation topic in section Gravitation of Physics – Class 11

Answer»

The CORRECT option is (d) [(2*G*M)/R]^1/2

To explain: If the object’s initial velocity is “v”, from the LAW of conservation of ENERGY, we have;

(m X v^2)/2 = (G x M x m)/R

v^2 = (2 x G x M)/R

Therefore; v = [(2 x G x M)/R]^1/2.



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