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What is the molarity of a solution containing 10 g of NaOH in 500 mL of solution ?A. `"0.25 mol L"^(-1)`B. `"0.75 mol L"^(-1)`C. `"0.5 mol L"^(-1)`D. `"1.25 mol L"^(-1)` |
Answer» Correct Answer - C No. of moles of NaOH=`10/40`=0.25 mol `M=(0.25xx1000)/500=0.5 mol L^(-1)` |
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