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What is the mount of KCI in grams which must be added in 100 g of water so that the freezing point is depressed by 2 K ? `(K_(f)"for water "= 1.86 K/m)`. |
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Answer» `W_(B)=(DeltaT_(f)xxM_(B)xxW_(A))/(iK_(f))` `=((2K)xx(74.5"g mol"^(-1))xx(0.1kg))/(2xx(1.86"K kg mol"^(-1)))=4` |
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