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What is the number fo photons fo light with a wavelngth fo ` 400 p m` that provide ` 1 J ` of energy ? |
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Answer» ` E//"photon" = (hc)/ ( lambda) = (6.625 xx 10^(-34) xx 3 . 0 xx 10^8)/( 4000 xx 10^(-12))` ` = 4 . 97 xx 10^(-17)J` `therefore` No . of photon in 1 J energy `= 1/( 4.97 xx 10 ^(-17))` ` 2. 01 xx 10 ^(16) ` photons . |
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