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What is the orbit angular momentum of a `d` electron?A. `(6 h)/(2 pi)`B. `(sqrt(6) h)/(2 pi)`C. `(12 h)/(2 pi)`D. `(sqrt(12) h)/(2 pi)` |
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Answer» Correct Answer - B (b) We know that for `d-"electron" l = 2` `mu = sqrt(l(l + 1)) (h)/(2 pi)` , `mu = sqrt(2(2 + 1)) (h)/(2 pi)` `mu = sqrt(2(2 + 1)) (h)/(2 pi)` , `mu = sqrt(6) (h)/(2 pi)`. |
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