1.

What is the pH of 1.0xx10^(-5) molar solution of KOH?

Answer»

Solution :`KOHtoK^(+)+OH^(-)`
`1XX10^(-5)` MOLAR `1xx10^(-5)mol`
`[OH^(-)]=1xx10^(-5)implies[H^(+)]=10^(-9)`
PH=`-log[H^(+)]` =-log `[10^(-9)]=9`


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