What is the power at the load of a shunt equalizer?(a) [(Vmax^2 X1^2)/(Ro(Ro^2+X1^2))](b) [(Vmax^2 X1^2)/(2Ro(Ro^2+X1^2))](c) [(Vmax^2 X1^2)/(3Ro(Ro^2+X1^2))](d) [(Vmax^2 X1^2)/(4Ro(Ro^2+X1^2))]I got this question in an interview for job.The origin of the question is Shunt Equalizer in section Filters and Attenuators of Network Theory

What is the power at the load of a shunt equalizer?(a) [(Vmax^2 X1^2)/

1.	What is the power at the load of a shunt equalizer?(a) [(Vmax^2 X1^2)/(Ro(Ro^2+X1^2))](b) [(Vmax^2 X1^2)/(2Ro(Ro^2+X1^2))](c) [(Vmax^2 X1^2)/(3Ro(Ro^2+X1^2))](d) [(Vmax^2 X1^2)/(4Ro(Ro^2+X1^2))]I got this question in an interview for job.The origin of the question is Shunt Equalizer in section Filters and Attenuators of Network Theory
Answer» CORRECT choice is (d) [(Vmax^2 X1^2)/(4Ro(RO^2+X1^2))] EXPLANATION: The power at the load of a series EQUALIZER is P=((Vmax jX1)/(2Ro(Ro+jX1)))^2 Ro =[(Vmax^2 X1^2)/(4Ro(Ro^2+X1^2))].

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