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InterviewSolution
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What is the principle value of \(sec^{-1}(\frac{2}{\sqrt{3}})\).(a) \(\frac{π}{6}\)(b) \(\frac{π}{3}\)(c) \(\frac{π}{4}\)(d) \(\frac{π}{2}\)I have been asked this question during an interview for a job.My question is based upon Inverse Trigonometric Functions Basics in section Inverse Trigonometric Functions of Mathematics – Class 12 |
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Answer» RIGHT option is (a) \(\FRAC{π}{6}\) To ELABORATE: Let \(SEC^{-1}(\frac{2}{\sqrt{3}})\)=y sec y=\(\frac{2}{\sqrt{3}}\) sec y=sec \(\frac{π}{6}\) ⇒y=\(\frac{π}{6}\) |
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