1.

What is the value of sin^-1(-x) for all x belongs to [-1, 1]?(a) -sin^-1(x)(b) sin^-1(x)(c) 2sin^-1(x)(d) sin^-1(-x)/2I had been asked this question by my college director while I was bunking the class.I'm obligated to ask this question of Inverse Trigonometry topic in chapter Inverse Trigonometric Functions of Mathematics – Class 12

Answer»

Correct OPTION is (a) -SIN^-1(x)

The BEST EXPLANATION: Let, θ = sin^-1(-x)

So, -π/2 ≤ θ ≤ π/2

=> -x = sinθ

=> x = -sinθ

=> x = sin(-θ)

Also, -π/2 ≤ -θ ≤ π/2

=> -θ = sin^-1(x)

=> θ = -sin^-1(x)

So, sin^-1(-x) = -sin^-1(x)



Discussion

No Comment Found

Related InterviewSolutions