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What is the ratio of the velocities of `CH_(4)` and `O_(2)` molecules no that they are associated with de broglie waves of equal wavelength ? |
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Answer» From the de Brogle relationship `lambda = (h)/(mv)` For `CH_(4) ,lambda_(ch4) = (h)/(m_(CH4) xx v_(CH4))`…….(i) For `O_(2),lambda_(O_2) = (h)/(m_(O_2) xx v_(O_2))`……(ii) Wavelength of `CH_(4)` and `O_(2)` is equal hence ` (h)/(m_(CH_4) xx v_(CH_4)) =(h)/(m_(O_2) xx v_(O_2))` `rArr ( v_(CH_4))/( v_(O_2))= (m_(O_2))/(mCH_4) = (32)/(16) = 2 ` `:, v_(CH_4) = 2 v_(O_2)` THe velocity of `CH_(4)` molecule is two times the velocity of `O_(2)`molecule |
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