What is the relationship between height “h” above the earth’s surface and a depth “d” below the earth’s surface when the magnitude of the acceleration due to gravity is equal? (Assume h < < R; where, R = Radius of the earth)(a) h = d(b) h = 2d(c) 2h = d(d) 3h = 2dI had been asked this question during a job interview.Question is taken from Acceleration due to Gravity below and above the Surface of Earth in division Gravitation of Physics – Class 11

What is the relationship between height “h” above the earth’s su

1.	What is the relationship between height “h” above the earth’s surface and a depth “d” below the earth’s surface when the magnitude of the acceleration due to gravity is equal? (Assume h < < R; where, R = Radius of the earth)(a) h = d(b) h = 2d(c) 2h = d(d) 3h = 2dI had been asked this question during a job interview.Question is taken from Acceleration due to Gravity below and above the Surface of Earth in division Gravitation of Physics – Class 11
Answer» Correct choice is (C) 2h = d Easy explanation: ACCELERATION due to gravity above the surface of the EARTH; g’ = [(GM1)/R^2] X [1 – (2h)/R)] Acceleration due to gravity below the surface of the earth; g’’ = (G x M1/R^3) x (R – d) g’ = g’’ Therefore; [(GM1)/R^2] x [1 – (2h)/R)] = (G x M1/R^3) x (R – d) 2h = d.

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