InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
What is the resolved form for a vector which is 5 units in long and is inclined at an angle of 45 degrees to the X axis?(a) \(\frac{1}{\sqrt{2}}\hat{i} + \frac{1}{\sqrt{2}}\hat{j}\)(b) \(\frac{5}{\sqrt{2}}\hat{i} + \frac{5}{\sqrt{2}}\hat{j}\)(c) \(\frac{5}{\sqrt{2}}\hat{i} + \frac{15}{\sqrt{2}}\hat{j}\)(d) \(\frac{10}{\sqrt{2}}\hat{i} + \frac{10}{\sqrt{2}}\hat{j}\)I have been asked this question in my homework.Question is from Motion in a Plane topic in division Motion in a Plane of Physics – Class 11 |
|
Answer» RIGHT option is (B) \(\frac{5}{\sqrt{2}}\hat{i} + \frac{5}{\sqrt{2}}\hat{j}\) To EXPLAIN I would SAY: The standard for is a(cos θ î + sin θ ĵ). Here, a = 5, and θ = 45 degrees. When we substitute this in the equation, we get, the resolved VECTOR as \(\frac{5}{\sqrt{2}}\hat{i} + \frac{5}{\sqrt{2}}\hat{j}\). |
|