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What is the set of values of p for which the roots of the equation 3x^2 + 2x + p(p – 1) = 0 are of opposite sign?(a) (-∞, 0)(b) (0, 1)(c) (1, ∞)(d) (0, ∞)This question was posed to me in semester exam.The doubt is from Applications of Quadratic Equations in portion Complex Numbers and Quadratic Equations of Mathematics – Class 11 |
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Answer» CORRECT choice is (b) (0, 1) The best I can explain: SINCE the roots of the given EQUATION are of OPPOSITE sing, So, products f the roots < 0 p(p – 1) / 3 < 0 p(p – 1) < 0 0 < p < 1 For REAL and distinct roots ½ – √21/ 6 < p < ½ + √21/6 |
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