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What is the shortest wavelength line in the Paschen series of `Li^(2+)` ion ?A. `(R)/(9)`B. `(9)/(R)`C. `(1)/(R)`D. `(9R)/(4)`

Answer» Correct Answer - 3
`(1)/(lambda)=RZ^(2)[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]=Rxx3^(2)[(1)/(3^(2))-(1)/(oo^(2))]" "rArr" "R or lambda=(1)/(R)`


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