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What is the symbol for the nucleus remaining after `._(20)Ca^(42)` undergoes `beta-`emissionA. `._(21)Ca^(42)`B. `._(20)Sc^(42)`C. `._(21)Sc^(42)`D. `._(21)Sc^(41)` |
Answer» Correct Answer - C `._(20)Ca^(42) rarr ._(21)Sc^(42) + ._(-1)e^(0)` |
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